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Java鍵盤輸入實(shí)例

時(shí)間:2020-11-11 19:30:06 java語言 我要投稿

Java鍵盤輸入實(shí)例

  引導(dǎo)語:java不像C中擁有scanf這樣功能強(qiáng)大的函數(shù),大多是通過定義輸入輸出流對(duì)象,以下是百分網(wǎng)小編分享給大家的Java鍵盤輸入實(shí)例,歡迎閱讀!

Java鍵盤輸入實(shí)例

  import java.util.Scanner;

  /**

  * 測試從鍵盤讀取用戶的輸入,關(guān)鍵類為Scanner

  * @author Administrator

  *

  */

  public class TestInput {

  public static void main(String[] args) {

  Scanner s = new Scanner(System.in);

  System.out.println("請(qǐng)輸入你的姓名:");

  String name = s.nextLine();

  System.out.println("請(qǐng)輸入你的年齡:");

  int age = s.nextInt();

  System.out.println("請(qǐng)輸入你的`工資:");

  float salary = s.nextFloat();

  System.out.println("你的信息如下:");

  System.out.println("姓名:"+name+"\n"+"年齡:"+age+"\n"+"工資:"+salary);

  }

  }

  說明:Scanner的對(duì)象的方法nextLine()接收字符和字符串類型的輸入;nextInt()接收int類型的;nextFloat()接收float類型的,相信后面的就不用一一列舉了吧。

  方法2:

  BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));

  System.out.print("Please input a number:");

  String str=reader.readLine(); //獲取字符串

  System.out.println("The number you input is:"+str);

  或

  InputStreamReader reader = new InputStreamReader(System.in);

  BufferedReader input = new BufferedReader(reader);

  System.out.print("Enter your age: ");

  String text = input.readLine();

  int age = new Integer(text).intValue();

  System.out.println("You are " + age + " years old, now,");

  int year = 2003 - age;

  System.out.println("so you were probably born in " + year);

  需要拋出io異常。

  import java.io.*;

  - @5 n0 _4 H: c( y: Hclass JavaIO_02N {' U- \9 P1 S, C2 m- R3 p& t

  public static void main(String param[])

  # u P+ ]+ a2 L6 O! V {: B7 A6 r3 ^ [4 ~

  String nn1="";//定義一個(gè)String整型對(duì)象nn1: b5 T) n6 E9 f4 @9 p

  BufferedReader distream = new BufferedReader(new InputStreamReader(System.in));

  , p1 J D/ B, @1 L" q6 P' a System.out.println("鍵入一個(gè)整數(shù)"); r& m/ H2 s' Q h" T( |+ j

  nn1=distream.readLine();//進(jìn)行輸入,并把輸入的數(shù)存入nn1中/ l, u4 y3 e5 R \

  ) J+ D7 n$ u; z% v3 Z7 g# S* w0 l int n1=Integer.parseInt(nn1);( z4 l# |( L/ q

  if(n1%2==0)

  . C6 b9 U$ D* F( y! K System.out.println(n1+"是一個(gè)偶數(shù)");

  3 ?! ^" c% C9 ], i- G9 L9 }/ b else( u- G, Z( Z* { V# _; _0 O

  System.out.println(n1+"是一個(gè)奇數(shù)"); 2 _; b) N, Q2 \4 W9 D: y$ t! E5 ~# J

  }% c! z' y( d6 d/ v# {. _7 Q

  }

  1 F: w6 M1 H) |8 j) O: e' C4 e

  & v" }5 S9 }& Y& l8 B

  " f9 G8 K, H+ A6 P% ajava不可能出現(xiàn)語句在任何方法,類之外的

  /* * Created on 2005-4-5

  * * TODO To change the template for this generated file go to

  * Window - Preferences - Java - Code Style - Code Templates

  */

  import java.io.BufferedReader;

  import java.io.IOException;

  import java.io.InputStreamReader;

  /**

  * @author Zhangql

  *

  * TODO To change the template for this generated type comment go to

  * Window - Preferences - Java - Code Style - Code Templates

  */

  public class EnterConsole

  {

  public static void main(String[] args) throws IOException

  {

  EnterConsole enterConsole = new EnterConsole();

  enterConsole.printConsoleChar();

  }

  /**

  * 從控制對(duì)接收一行字符串,然后輸出到控制臺(tái)

  * @throws IOException

  */

  public void printConsoleLine() throws IOException

  {

  BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

  String str = null;

  System.out.println("Enter your value:");

  str = br.readLine();

  System.out.println("your value is :"+str);

  }

  /**

  * 從控制臺(tái)接收一個(gè)字符

  * 然后打印到控制臺(tái)上

  * @throws IOException

  */

  public void printConsoleChar() throws IOException

  {

  System.out.print("Enter a Char:");

  char i = (char) System.in.read();

  System.out.println("your char is :"+i);

  }

  }

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